I forgot to answer this: At 23:45 18.01.06, Joel Salomon wrote: >What it seems > {\hidewidth\vphantom{\i}\cr\smash{$k$}} >is doing is putting a $k$ somewhere and making the rext of TeX think >it's actually an 'i' there. Is that correct? Yes, it is! And it is the same with the more recent \rlap solution. --Uwe.